Вопрос школьника
After a certain period of time after the start of the reaction equation which СО2(g) + С(s) = 2СО(s), concentration of carbon oxide is reduced by 4 times. how many times this will reduce the reaction rate compared to the initial ?
Ответ от учителя
The reduction of the concentration of carbon oxide by 4 times means that the concentration of CO in the reaction mixture has decreased from its initial value by a factor of 4. This can be expressed mathematically as:
[CO]final = [CO]initial / 4
Since the reaction equation is:
CO2(g) + C(s) = 2CO(g)
We can use the stoichiometry of the reaction to relate the concentration of CO to the concentration of CO2. At the start of the reaction, the concentration of CO2 is equal to the initial concentration of CO, since there is no CO in the reaction mixture yet. Therefore:
[CO2]initial = [CO]initial
After a certain period of time, the concentration of CO2 will have decreased due to its consumption in the reaction. Let’s assume that the concentration of CO2 has decreased by a factor of x. This means that:
[CO2]final = [CO2]initial / x
Using the stoichiometry of the reaction, we can relate the final concentration of CO to the final concentration of CO2:
[CO]final = 2[CO2]final
Substituting the expressions for [CO2]final and [CO]final in terms of their initial values and the factor x, we get:
[CO]initial / 4 = 2[CO]initial / x
Simplifying this equation, we get:
x = 8
This means that the concentration of CO2 has decreased by a factor of 8 after a certain period of time. Therefore, the reaction rate will also decrease by a factor of 8 compared to the initial rate, since the rate of a chemical reaction is proportional to the concentrations of the reactants.
